Cellular Homology, Skeleton

Skeleton

Let S be a cw complex. The collection of cells in S with dimension p or less is the p skeleton of S. This is sometimes denoted Sp.

Skeleton is Closed

Take the closure of Sp by taking the union of the closure of each cell of dimension p or less. The boundary of each cell is contained in cells of lower dimension, and is already in Sp. Therefore Sp is closed in S.

S0 is Discrete

Let y be any point in S0. Let T be the points of S0 without y. Intersect T with a closed cell E. The boundary is covered by finitely meny cells, hence finitely many points live in the intersection. Since S is hausdorff, each point is closed. The intersection consists of finitely many points, and it too is closed. This holds for each cell, hence T is closed. Since y was arbitrary, every point is open, and S0 has the discrete topology.

Sp is a Subcomplex

The cells and characteristic functions of Sp are inherited from S. Each boundary is covered by finitely many cells at lower dimensions. We only need verify the topology.

Let T ⊆Sp intersect each closed cell in a closed set. Let E be a cell in Sp. Since Sp is closed, the closure of E is also in Sp. We already know T intersect the closure of E is closed. And this lives in a closed set in S, hence it is closed in S.

Let E be a cell outside of Sp. Its boundary is covered by a finite number of cells from Sp. Each intersection is closed, and their finite union is closed. This holds for every cell, hence T is closed in S. Restrict to Sp, and T is closed in Sp. The topology is right, and Sp is a subcomplex of S.

Direct Limit

The union of all p skeletons gives S. This is a union where each skeleton builds upon the previous. If you like category theory, it is technically a direct limit.

The subset T is closed in S iff it is closed in each skeleton Sp. This is clear if you remember that T is closed iff its intersection with every cell is closed. The latter is true iff T is closed in each cell of dimension p or less, for each p - and this holds iff T is closed in each Sp.