Assume you are paid n times a year, receiving 6%/n each time. At the end of the year your funds are multiplied by (1+6%/n)n. Take the limit as n approaches infinity. Actually we will take the limit of the log, which is n×log(1+6%/n). This is the product of two quantities; one approaches ∞ and the other approaches 0. Instead of multiplying by n, divide by 1/n, hence we can use L'hopital's rule. After canceling -n2, the result is 6% over 1+6%/n. This approaches 6% for large n. This was the log of our expression, hence our assetts are multiplied by E6% at the end of the year. This is an actual increase of 6.18%. If the bank holds the money for half the year, you will receive E3%. Many institutions use this formula for continuously compounded interest. You are paid for the precise number of hours that your money is in their hands.