Sometimes the alternating restriction is dropped in order to simplify the problem. In this case we can compute the number of permutations using inclusion exclusion. To seat at least i couples together, select i couples out of n, order them male-female or female-male, and place them at the table along with the other 2n-2i people. This yields a formula:
(n:i) × 2i × (2n-i-1)!
Take the alternating sum of this expression, as i runs from 1 to n, to find the number of permutations with at least one couple seated together. Subtract this from (n-1)! to get the no-couple permutations.