Galois Extensions, Finite Fields
Finite Fields
As you recall, the
automorphisms
of a finite field form a cyclic group.
In fact this cycle has length n, when the field has order pn,
and the dimension of this field, over Zp,
is also equal to n.
The dimension equals the size of the group, hence the extension is galois.
Furthermore, the field of order pn is galois over every intermediate extension.
Therefore every finite extension of every finite field is galois.
Let F be the algebraic closure of Zp.
Since F has all the roots of everything, it is normal over Zp.
Let u be any element in F.
Since Zp(u) is galois, some automorphism moves u.
This automorphism
extends to all of F.
Thus an automorphism of F moves u, and F is galois over Zp.
The same proof shows F is galois over every finite field.