Note that R is a subring of the product ring. Since every ring homomoorphism carries 1 to 1, project down to Si, and h maps 1 in R to 1 in Si.
Unlike direct product, there are many nonisomorphic subdirect products of Si. We'll see this later on.
To avoid a trivial representation, each hi must have a nonzero kernel, and since R embeds, the intersection of these kernels Ki is 0.
If R has only trivial subdirect product representations, R is subdirectly irreducible.